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u=27cm
h1=7cm
f=18cm
v=?
Therefore by, lens formula
1/f=1/v-1/u
1/18=1/v-1/(-27)
v=-54cm
I.e distance from the mirror of image is 54cm.
therefore,nature of image is real and inverted.
therefore by magnification formula,
h2/h1=-v/u
h2/7=-54/27
h2=-54×7/27
h2=-2×7
h2=-14cm
therefore height of the image is -14cm
h1=7cm
f=18cm
v=?
Therefore by, lens formula
1/f=1/v-1/u
1/18=1/v-1/(-27)
v=-54cm
I.e distance from the mirror of image is 54cm.
therefore,nature of image is real and inverted.
therefore by magnification formula,
h2/h1=-v/u
h2/7=-54/27
h2=-54×7/27
h2=-2×7
h2=-14cm
therefore height of the image is -14cm
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