Question

pls ans me...
I'm confused...​

Answer 1

Answer:

See the attachment

hope it helps..... mark brainliest

Answer 2

Given that :

$\frac{ {x}^{2} + 1}{x} = 2 \frac{1}{2} \\ \\ = > x + \frac{1}{x} = \frac{5}{2}$

Now, we have to find the value of :

${(x - \frac{1}{x}) }^{2} = {(x + \frac{1}{x} )}^{2} - 4x \times \frac{1}{x} \\ \\ = > {(x - \frac{1}{x}) }^{2} = {( \frac{5}{2} )}^{2} - 4 = \frac{25}{4} - 4 = \frac{9}{4}$

And

${x}^{3} - \frac{1}{ {x}^{3} } = {(x - \frac{1}{x} )}^{3} + 3x \times \frac{1}{x} (x - \frac{1}{x} ) \\ \\ = > {x}^{3} - \frac{1}{ {x}^{3} } = {( \frac{9}{4}) }^{3} + 3 \times \frac{9}{4} \\ \\ = > {x}^{3} - \frac{1}{ {x}^{3} } = \frac{729}{64} + \frac{27}{4} = \frac{729 + 432}{64} = \frac{1161}{64}$

I hope it will be helpful for you ✌️✌️

Mark it as brainliest and Fóllòw MË ☺️☺️