Question

pls ans my question guys

Answer 1

$\huge\mathcal{Answer \ :-}$

$\mathsf{Let}$

$\mathsf{Length, \ l \ = \ 4x}$

$\mathsf{Breadth, \ b \ = \ 3x}$

$\mathsf{Height, \ h \ = \ 2x}$

$\mathsf{Given \ TSA \ of \ Cuboid \ = \ 468 \ cm^2}$

$\mathsf{Using \ formula}$

$\mathsf{TSA \ of \ Cuboid \ :-}$

$\mathsf\red{= \ 2(lb + bh + hl)}$

•°•$\mathsf{2(lb + bh + hl) \ = \ 468}$

$\mathsf{2[(4x)(3x) + (3x)(2x) + (2x)(4x)] \ = \ 468}$

$\mathsf{2(12x^2 + 6x^2 + 8x^2) \ = \ 468}$

$\mathsf{2(26x^2) \ = \ 468}$

$\mathsf{26x^2 \ = \ 468/2}$

$\mathsf{26x^2 \ = \ 234}$

$\mathsf{x^2 \ = \ 234/26}$

$\mathsf{x^2 \ = \ 9}$

$\mathsf{x \ = \ 3}$

$\mathsf{Now,}$

$\mathsf\red{Length \ = \ 4x \ = \ 4(3) \ = \ 12 \ cm}$

$\mathsf\red{Breadth \ = \ 3x \ = \ 3(3) \ = \ 9 \ m}$

$\mathsf\red{Height \ = \ 2x \ = \ 2(3) \ = \ 6 \ m}$

$\huge\mathbb{Hope \ this \ helps.}$

Answer 2

Let length, breadth and height of a cuboid is 4a , 3a and 2a.



Total surface area of cuboid = 468


2 ( LB + BH + HL ) = 468



2 ( 4a• 3a + 3a• 2a + 2a• 4a ) = 468





12a² + 6a² + 8a² = 234




26a² = 234


a² = 234/26


a² = 9


a = √9 = 3


Length of cuboid = 4a = 4 × 3 = 12 cm.


Breadth of cuboid = 3a = 3 × 3 = 9 cm.


And,

Height of cuboid = 2a = 2 × 3 = 6 cm.