Question

pls ans my question .... with picture also and solution too....​

Answer 1

Answer:

$\huge\colorbox{yellow}{Given\:-}$

The rectangular formed by the path and the field is 200 m × 60 m

$\huge\colorbox{yellow}{To\:Find\:-}$

• The area of the path

• The cost of constructing the path at ₹ 15 per m

$\huge\colorbox{yellow}{Solution\:-}$

$\small\underbrace\mathrm\red{Using\:formula}$

$\boxed{Area\:of\:rectangle = length \times breadth}$

A T Q,

Length = 200 - 10 = 190 m

Breadth = 60 - 10 = 50 m

Area = l × b = 9500 m

$Area of outer path = Total area - Inner area$

$= 200 \times 60 - 9500$

$= 12000 - 9500$

$\pink{ = > 2500 \: {m}^{2}}$

The cost of constructing the path

$= 2500 \times 15$

$\pink{ = > 37500}$

$\huge\colorbox{yellow}{Thank\:You}$