Question

pls ans of the math
pls don't spam​

Answer 1

Step-by-step explanation:

$x²+y²=5xy \\ \\ now \\ \frac{x²}{y²} + \frac{y²}{x²} \\ = \frac{ {x}^{4} + {y}^{4} }{ {x}^{2} {y}^{2} } \\ = \frac{ {(x²)}^{2} + {(y²)}^{2} }{(xy)²} \\ = \frac{(x² + y²)²-2x²y²}{(xy)²} \\ = \frac{(5xy)²-2x²y²}{(xy)²} \\ = \frac{25x²y²-2x²y2}{x²y²} \\ = \frac{23x²y²}{x²y²} \\ = 23 \\ \\ \\ here \\ i \: have \: used \\ (a+b)²=a²+2ab+b² \\ (a+b)²-2ab = {a}^{2} + {b}^{2} \\ so \: (x + y)^{2} - 2xy = {x}^{2} + {y}^{2}$