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Mass of bullet = 10g or 0.01kg
velocity of bullet = 150m/s
Mass of wood = 5kg
It's velocity = 0m/s (cause it's in rest)
Total momentum before the impact =m1v1+m2v2
=0.01kg×150 + 5×0
=1.5 +0 = 1.5kgm/s
Now, after the impact
Mass = 0.01+5 = 5.01kg
velocity = V
According to law of conservation of momentum, total momentum remains conserved during a collision.
So,
Total Momentum before impact = Total Momentum after impact
= 1.5 = 5.01×V
= V = 1.5/5.01 = 0.3m/s
So,
The combined velocity is 0.3m/s
Cheers!
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