Question

pls ans question 32 properly and no spam pls​

Answer 1

Let us make a table like this :

Element    %     atomic mass   relative no.   simplest ratio

O              34.55        16        34.55/16 = 2.16       2.16/2.16 = 1

H               13.05         1           13.05/1 = 13          13.05/2.16= 6

C                52.4          12         52.4/12=4.37       4.37/2.16 = 2

All these are approx .

Empirical formula = C₂H₆O