Question

Pls ans the attachment

Answer 1

Answer:

60 km|S2 is the answer bro

Answer 2

Answer:

Question :-

$\mapsto$ A bullet comes out of the barrel of gun of length 2 m with a speed of 600 m/s. The average acceleration of the bullet ?

Given :-

$\mapsto$ A bullet comes out of the barrel of gun of length 2 m with a speed of 600 m/s.

To Find :-

$\mapsto$ What is the average acceleration of the bullet.

Formula Used :-

$\clubsuit$ Third Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\pink{v^2 =\: u^2 + 2as}}}$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• s = Distance Covered

Solution :-

Given :

★ Final Velocity (v) = 600 m/s

★ Initial Velocity (u) = 0 m/s

★ Distance Covered or Length = 2 m

According to the question by using the formula we get,

$\small\longrightarrow \sf (600)^2 =\: (0)^2 + 2a(2)$

$\small\longrightarrow \sf 600 \times 600 =\: 0 \times 0 + 4a$

$\small\longrightarrow \sf 360000 =\: 0 + 4a$

$\small\longrightarrow \sf 360000 - 0 =\: 4a$

$\small\longrightarrow \sf 360000 =\: 4a$

$\small\longrightarrow \sf \dfrac{\cancel{360000}}{\cancel{4}} =\: 4a$

$\small\longrightarrow \sf \dfrac{90000}{1} =\: a$

$\small\longrightarrow \sf\bold{\purple{a =\: 90000\: m/s^2}}$

Now, we have to convert acceleration m/s² into km/s² :

$\small\longrightarrow \sf Acceleration =\: 90000\: m/s^2$

$\small\longrightarrow \sf Acceleration =\: \dfrac{90\cancel{000}}{1\cancel{000}}\: km/s^2\: \: \bigg\lgroup \small\sf\bold{\pink{1\: m/s^2 =\: \dfrac{1}{1000}\: km/s^2}}\bigg\rgroup$

$\small\longrightarrow \sf Acceleration =\: \dfrac{90}{1}\: km/s^2$

$\small\longrightarrow \sf\bold{\red{Acceleration =\: 90\: km/s^2}}$

${\small{\bold{\underline{\therefore\: The\: average\: acceleration\: of\: the\: bullet\: is\: 90\: km/s^2\: .}}}}$

Hence, the correct options is option no (1) 90 km/s² .