pls ans the ques following
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Step-by-step explanation:
Angle ADB is 90° bcz triangle in a semi circle is also a right angled triangle
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AngleDBC= AngleCAD(angle in the same segment )
In triangle ADE
Angle DAE +angle ADE+ Angle AED =180
25+angle ADE +60 = 180
85 + angle ADE =180
angle ADE = 180-85 = 95
angle ADE = angle ADB = 95
In triangle ADE
Angle DAE +angle ADE+ Angle AED =180
25+angle ADE +60 = 180
85 + angle ADE =180
angle ADE = 180-85 = 95
angle ADE = angle ADB = 95
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