Question

pls ans the ques with steps​

Answer 1

Step-by-step explanation:

SP = Rs.800 ; Profit = 25%

CP = SP x 100100+P% = 800 x 100100+25 = 640

Now, CP = Rs.640

Loss = 25% = 25% of Rs.640 = Rs.160

Thus, SP = CP - Loss = Rs.640 - Rs.160 = Rs.480

Subject: Profit and Loss - Quantitative

hope helpful to you

Answer 2

$\mathtt{ANSWER}$

Given,

Selling price of the article = Rs 800

loss % = 20%

Let the Cost price of the article be x , then ,

Loss = Cost price - selling price = x - 800

Now , we know that

$loss \: percent \: = \frac{loss}{cost.price} \times 100$

According to the question ,

$20 = \frac{x - 800}{x} \times 100$

$\implies \: 20 \times x = (x - 800) \times 100 \\ \implies \: 20x = 100x - 80000 \\ \implies \: 100x - 20x = 80000 \\ \implies \: 80x = 80000 \\ \implies \: x = \frac{80000}{80} \\ \implies \: x = 1000$

Therefore, the cost price of the article is 1000 Rs.

Now

Cost Price = Rs 1000

and ,

profit % = 25%

let the Selling price in this case be y , then ,

Profit = Selling price - cost price = y - 1000

$profit \: percent \: = \frac{profit}{cost.price} \times 100$

$\implies \: 25 = \frac{y - 1000}{1000} \times 100 \\ \implies \: 25 = \frac{y - 1000}{10} \\ \implies25 \times 10 = y - 1000 \\ \implies \: 250 = y - 1000 \\ \implies \:y = 1000 + 250 \\ \implies \: y = 1250$

Therefore , the shopkeeper should sell th article at Rs 1250 to make a profit of 25%.