Math, asked by shnk021, 1 month ago

Pls ans the question attached in file pls
emergency​

Attachments:

Answers

Answered by guptaseema867
0

Answer:

I don't understand the question can you please mark as brain list

Answered by sonasweety982
1

Answer:

g(X)=2x^2-15x+32=0

Step-by-step explanation:

the given equation in the form of ax^2+bx+c

a=2

b= -5

c=7

alpha+beta=-b/a

alpha+beta=-(-5)/2=5/2

(alpha)*(beta)=c/a=7/2

given alpha=alpha+2beta

ß=2alpha+ß

alpha+ß=alpha+2ß+2alpha+ß

alpha+ß=3alpha+3ß=3(alpha+ß)

alpha+ß=3(5/2)=15/2

alpha*ß=2alpha^2+4alpha*ß+alpha*ß+2ß^2

=2(alpha^2+ß^2+2alpha*ß)+alpha*ß

=2(alpha+ß)^2+alpha*ß

=2(5/2)^2+7/2

=25/2+7/2=32/2=16

sub these values in x^2-(alpha+ß)X+alpha*ß=0

x^2-15/2x+16=0

2x^2-15x+32=0

Similar questions