Math, asked by DDR108, 8 months ago

pls ans thes question​

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Answered by tarracharan
6

{\bold{As\: \: PR || TS,}}

{\bold{\blue{Angle \: QPR = Angle \: QOS=105°}}}

{\bold{Angle\: QTS \: is \:exterior \:angle \:of\: ∆TOQ}}

{\bold{\red{Angle\:QTS=Angle\:QOS + Angle\:PQT}}}

{\bold{\red{Angle\:QTS=105°+ 25°}}}

{\boxed{\red{Angle\:QTS=130°}}}

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Answered by jaswasri2006
0

∠T = ∠P + ∠Q

∠T = 105° + 25° = 130°

  • ∠STQ = 130°

hope this will help u

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