Question

pls ans thi quickly pls pls

Answer 1

Heya !!!





GIVEN THAT,


( X -1) and (X+2) are factor of Polynomial X³+10X²+AX+B





(X-1) = 0 OR ( X +2) = 0



X = 1 OR X = -2



P(X) = X³ + 10X² + AX + B



P(1) = (1)³ + 10 × (1)² + A × 1 + B




=> 1 + 10 + A + B = 0



=> A + B = -11 -------(1)



Also,



(X) = -2



P(-2) = (-2)³ + 10 × (-2)² + A × -2 + B




=> -8 +40 -2A + B = 0




=> 32 -2A + B = 0



=> -2A + B = -32 -------(2)



From equation (2) we get ;




-2A + B = -32



B = -32 + 2A ------(3)





Putting the value of B in equation (1)




A + B = -11



A + ( -32 + 2A) = -11



A - 32 + 2A = -11


3A = -11 + 32



3A = 21




A = 21/3




A = 7



Putting the Value of A in equation (1)



A + B = -11



7 + B = -11


B = -11-7



B = -18



Hence,



A = 7 and B = -18



HOPE IT WILL HELP YOU...... :-)