Question

pls ans this as fast as possible

Answer 1

TIME OF JOURNEY =5SECOUND

HEIGHT = 125m


✺ TOTAL DI STANCE =

125+125=250m


✸REASON✍✍✍

Object first go upward

and then fall back so total distance is addition
of both length

✺ TOTAL DISPLACEMENT


0

✷REASON ✍✍✍✍

DISPACEMENT is a vector quantity it has


direction and magnitude


so
when body fall back then it is opposite

in direction.

$= > 125 + ( - 125)$
$= > 0$



✺ AVERAGE SPEED



$\frac{total \: distance}{total \: time}$





$= > \frac{250}{5}$




$= > 50 \: \: m {s}^{ - 1}$




✺AVERAGE VELOCITY



$\frac{total \: displacment}{total \: time}$


$\frac{0}{5}$

$ans \: \: \: 0$

Answer 2

3 one is your answer