Pls ans this asap
Solve the following system of linear equations using inversion method.
2x+y+z=8
5x-3y+22=3
7x+y+3z=20
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Answer:
Step-by-step explanation:
From first equation
z = 8-2x-y
Substituting it in third equation gives
7x+y+3(8-2x-y) = 20
7x+y+24-6x-3y = 20
x-2y = -4
x=2y-4
Substituting in second equation gives
5(2y-4) - 3y = -19
10y-20-3y=-19
7y = 1
y = 1/7
Rest you can substitute and find..
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