Question

pls ans this correctly i will mark you the brainiest

Answer 1

Answer:

In △ABC, we have

∠A + ∠B + ∠C = 180° (Since, sum of the angles of a △ is 180°)

⇒ 1/2∠A + 1/2∠B + 1/2∠C = 180°/2

⇒ 1/2∠A + ∠1 + ∠2 = 90°

∴ ∠1 + ∠2 = 90° - 1/2∠A …..(i)

Now, in △OBC, we have:

⇒ ∠1 + ∠2 + ∠BOC = 180° [ Since,sum of the angles of △ is 180°)

⇒ ∠BOC = 180° - (∠1 + ∠2)

⇒ ∠BOC = 180° - (90° - 1/2∠A) [ using (i) ]

⇒ ∠BOC = 180° - 90° + 1/2∠A

∴ ∠BOC = 90° + 1/2∠A

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