Question

pls ans this

pls ans 6 question
ans is 7
i tried but cant slv the question ​

Answer 1

Answer:

Given=>

Length of the rectangular sheet=44cm

Breadth of the rectangular sheet =20cm

Now,

since this is a rectangular sheet used to make the Cylinder we have=>

Circumference of the Cylinder's base circle as=>44cm(which was length of rectangular sheet)

and, Height of cylinder => 20cm.[which was breadth of rectangular sheet]

We know that

Circumference of a circle = 2× $\pi$×r

=>44 =2× $\frac{22}{7}$ × r

=>$\frac{22 * 7}{22}$ = r

                                      =>r =7cm.

Hence, the radius of the cylinder is 7cm.

Remember

1]Area of circle = 2×$\pi$×r^2

2]Circumference = 2× $\pi$×r

Answer 2

As rectangular sheet is rolled along its length

So circumference of cross sectional cylinder becomes equal to length

Length = 44

circumference of cross section= 2 pie r

2 pie r = 44

r = 44/2 pie = 44/ 2× 22/7

= 7 cm