Question

Pls Ans. this ques. and give the explanation too...I will mark the best ans as the brainliest. :D

Answer 1

To solve :-

$: \longrightarrow \tt{5y - \dfrac{y + 1}{2} = \dfrac{y - 1}{4} + y}$

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Solution :-

$: \implies \tt{5y - \dfrac{y + 1}{2} = \dfrac{y - 1}{4} + y}$

Transporting of LHS and RHS

${ : \implies \tt5y - y= \dfrac{y - 1}{4} + \dfrac{y + 1}{2} }$

Simplifying LHS and RHS

${ : \implies \tt 4 y= \dfrac{y - 1}{4} + \dfrac{y + 1}{2} }$

Taking LCM

${ : \implies \tt 4 y= \dfrac{y - 1 + 2(y + 1)}{4} }$

${ : \implies \tt 4 y= \dfrac{y - 1 + 2y + 2}{4} }$

${ : \implies \tt 4 y= \dfrac{3y + 1}{4} }$

Now cross multiplication

${ : \implies \tt (4 y)4=(3y + 1) }$

${ : \implies \tt 8y=3y + 1}$

Transporting 3y from RHS to LHS

${ : \implies \tt 8y - 3y= 1}$

${ : \implies \tt 5y= 1}$

$\boxed{ \purple{ : \implies \tt y= \dfrac{ 1}{5}}}$

This is the required answer..!