Math, asked by ammukitty, 1 year ago

pls....ans this.....question.......​

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Answered by adarsharyan46
0

Answer:

first thing first proofs the triangles ABD and ACE congruent

Angle 1=2(given)

angle B=C (given)

BD=CE (given)

therefore the triangles are congruent...by ASA

now since Triangle ABF =ACE

AD=AC(by CPCT)

HOPE IT HELPS:-D

Answered by Anonymous
0

Answer:

see in ∆ ABC and ∆ AED

<B=<E

<BAC=<BAD+<CAD

<EAD=<EAC+<CAD

SINCE <BAD=<EAC. ....(given)

therefore <BAC=<EAD

BC=BD+DC

ED=EC+DC

SINCE BD=EC ........(given)

therefore BC=ED

THEREFORE BY AAS CRITERIA

∆ABC OS CONGURENT TO ∆AED

IN ∆ABD and ∆AEC

<1=<2

<B=<E

BD=EC

THEREFORE BOTH TRIANGLES ARE CONGURENT TO EACH OTHER ...BY AAS CRITERIA

THERFORE

BD=EC BY CPCT

HOPE IT HELPS.......

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