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Area under the curve of a velocity time graph gives the displacement of the body.
=1*20/2 + 6*20 + 2*10/2
=10 + 120 + 10
=140m
here, the motion is in straight line
Hence, Distance covered = Displacement = 140m
So, (3) 140,140 will be the answer
=1*20/2 + 6*20 + 2*10/2
=10 + 120 + 10
=140m
here, the motion is in straight line
Hence, Distance covered = Displacement = 140m
So, (3) 140,140 will be the answer
Answered by
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As it is given inthe question that the particle moved in a straight line, so the displacement and the distance will be equal
Distance/Displacement in velocity-time graph is given by the area under the curve.
The area under the curve in this case
=[(1/2)x1x20]+[6x20]+[(1/2)x2x10]
=10+120+10
=140
So, the correct option is Option 3
Distance/Displacement in velocity-time graph is given by the area under the curve.
The area under the curve in this case
=[(1/2)x1x20]+[6x20]+[(1/2)x2x10]
=10+120+10
=140
So, the correct option is Option 3
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