Question

pls ans this question ​

Answer 1

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Given,

⇒ AB and CD intersect at M

⇒ PM is perpendicular to AB (∠AMP = ∠ BMP)

⇒ DMB= 20°

To find,

⇒ a, b, c and d

Proof,

⇒ ∠DMB = ∠AMC = 20° (Vertically Opposite angles)

     ⇔ a = 20°

⇒ ∠BMP = ∠AMP= 90° ( as PM⊥AM)

     ⇔ d = 90°

⇒∠DMB + ∠PMD = ∠BMP

⇒ 20° + ∠PMD = 90°

⇒ ∠PMD = 90° - 20° = 70°

     ⇔ c = 70°

⇒ c + d = b (V.O.A)

⇒ 70° + 90° = b

     ⇔ b = 160°

Hence,

a = 20°,

b= 160°,

c = 70°,

d = 90°

Hope it helps :)