Question

pls ans this question

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Answer 1

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Answer 2

$\huge \fbox \purple{answer}$

$initial \: velocity \: u = 0 \\ final \: velocity \: v = \\ hieght \: s = 19.6m$

$using \: third \: law \: of \: motion \: \: \\ v ^{2} + u ^{2} + 2gs$

$v ^{2} = 0 + 2 \times 9.8 \times 19.6 \\ \ \\ v ^{2} = 384.16 \\ v = 19.6m$

hope this helps u thank u