Question

pls ans this question in paper probably by handwriting.

Answer 1

we know,

n(AUBUC) =n(A) + n(B) +n(C) -n(AUB)-n(BUC)-n(CUA)+n(AUBUC)

=48 + 51 + 40 - 11 - 10 -9 +4
= 139 -30 +4
= 113

hence ,

n(AUBUC) = 113

we also know,

n' (AUBUC) = n(u ) -n(AUBUC)
=120 -113
=7
hence answer is 7