Question

pls ans this quick.....

Answer 1

Answer

Given -

m = 10 kg

μ = 0.5

$\longrightarrow$where m is mass of block.

$\longrightarrow$μ is coefficient of static friction.

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Formula used -

$F_{smax}$ = μ N

where

$\longrightarrow$$F_{smax}$= Max. value of static friction.

$\longrightarrow$μ is coefficient of static friction.

$\longrightarrow$N is normal force.

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N = mg

where

$\longrightarrow$N is normal force.

$\longrightarrow$m is mass of object.

$\longrightarrow$g is acceleration due to gravity.

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If the object is not moving then,

$F_{smax} = F_{applied}$

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F = ma

where

$\longrightarrow$m is mass of object.

$\longrightarrow$a is acceleration.

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Solution

$\longrightarrow$μ = 0.5

$\longrightarrow$N = mg = 10 × 10 = 100N

$F_{smax}$ = 0.5 × 100

$F_{smax}$ = 50 N

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As the object is not moving,

$F_{smax} = F_{applied}$

$\longrightarrow$$F_{applied}$ = 50N

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$F_{applied}$ = ma = 50N

$\longrightarrow$10 × a = 50N

$\implies$a = 5 m/s²

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Thanks

Answer 2

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Explanation:

1. a))) 5ms-¹ is answer