Question

Pls ans this quickly​

Answer 1

a)

In triangle AEC, AE = 10 cm, CE = 8cm, Angle C = 90 degress

Using pythagoras theorem,

(AE)^2 = (AC)^2 + (AE)^2

100 - 64 = (AC)^2

AC = 6 cm = BC ( C is midpoint of AB, so AC = CB )

b)

In triangle ACE and BCE

AC = BC ( c is midpoint )

EC = EC ( common side )

angle ECA = angle ECB ( 90 degrees)

Therefore, triangle ACE is congruent to triangle BCE ( by SAS congruent critrion)

So, AE = BE ( congruent parts of congruent triangles are equal )

Ratio of AE and BE, AE:BE = 1:1

c)

As AE = BE, AEB is an isosceles triangle

d)

CE is the altitude as well as median of triangle AEB

e)

As EC is median, it divides triangle AEB into 2 equal areas, area of BCE is half of ABE

so ratio of ABE and BCE = 2:1

Mark as brainliest answer pls.

Answer 2

my hand writting is so bore

hope you got the ans

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