Question

pls ans this step by step​

Answer 1

Answer:

b-a

Step-by-step explanation:

bx+ay=a sq.+b sq. .......(1)

ax+by=0 .......(2)

By adding eq (1)×b and eq (2)×a

we get

=> [(1)×b]+[(2)×a]

=> b(bx+ay)+a(ax+by) =b(a sq.+b sq.)+a(0)

=>b sq.x+aby+a sq. x-aby= b(a sq.+b sq.)

=>a sq.x+ b sq.x=b(a sq.+b sq.)

=>x(a sq.+b sq.)=b(a sq.+b sq.) ...... (3)

Substituting value of x eq(2)

we get

=>a(b)-by=0

=>ab-by=0

=> -by = -ab

=> by=ab

=> y=a ......(4)

By subtracting eq (4) from (3)

we get

=> x-y=b-a

Answer 2

Answer:

Hmmmm English language......