Question

pls ans this step by step​

Answer 1

☯ GiveN :

↪2x + 3y = 0

↪4x - 3y = 0

$\rule{200}{1}$

☯ To FinD :

We have to find the value of (x + y)

$\rule{200}{1}$

☯ SolutioN :

2x + 3y = 0 ......(1)

4x - 3y = 0 .......(2)

From equation (1).

$\sf{\dashrightarrow 2x = -3y} \\ \\ \sf{\dashrightarrow x = \frac{-3y}{2}}$

Put value of x in equation (2).

$\sf{\dashrightarrow \cancel{4} \bigg( \frac{-3y}{\cancel{2}} \bigg) - 3y = 0} \\ \\ \sf{\dashrightarrow 2(-3y) - 3y = 0} \\ \\ \sf{\dashrightarrow -6y - 3y = 0} \\ \\ \sf{\dashrightarrow -9y = 0} \\ \\ \sf{\dashrightarrow y = 0} \\ \\ \Large{\implies{\boxed{\boxed{\sf{y = 0}}}}}$

$\rule{200}{2}$

Now, put value of y in equation (1).

$\sf{\dashrightarrow 2x + 0 = 0} \\ \\ \sf{\dashrightarrow 2x = 0} \\ \\ \sf{\dashrightarrow x = 0} \\ \\ \Large{\implies{\boxed{\boxed{\sf{x = 0}}}}}$

$\rule{200}{2}$

Now,

$\sf{\dashrightarrow x + y } \\ \\ \sf{\dashrightarrow 0 + 0 } \\ \\ \sf{\dashrightarrow 0} \\ \\ \Large{\implies{\boxed{\boxed{\sf{x + y = 0}}}}}$

$\therefore$ Option A is correct.

Answer 2

$\mathfrak \blue{ option \: a) \: 0 \: is \: the \: right \: answer}$