Question

pls ans this with process. Step by step.

Answer 1

Given:

$\frac{3}{ \sqrt{3} - \sqrt{2} } = a \sqrt{3} - b \sqrt{2}$

L.H.S

$= \frac{3}{ \sqrt{3} - \sqrt{2} } \\ \\ = \frac{3}{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \\ = \frac{3( \sqrt{3} + \sqrt{2} }{3 - 2} \\ \\ = 3 \sqrt{3} + 3 \sqrt{2}$
on comparing, we have,

a= 3 and b= 3

Answer 2

Hey there!

$\frac{3}{ \sqrt{3} - \sqrt{2} } \\ \frac{3}{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \frac{3 \sqrt{3} + 3 \sqrt{2} }{3 - 2} \\ \frac{3 \sqrt{3} + 3 \sqrt{2} }{1} \: \: \: \\ \: \: \: \: \: \: \: \: \: \: or \\ \: \: \: 3 \sqrt{3} + 3 \sqrt{2} = a \sqrt{3} - b \sqrt{2}$

So values of a = 3 and b = -3.