Question

pls ans to be brainlist

Answer 1

since total are 500 and defective are15 then remaining r485 then probability of non defective tube will be 485/ 500

Answer 2

Given the total number of electric tubes = 500.

 Given that number of defective tubes = 15.

Then, the number of non-defective tubes = 500 - 15

                                                                      = 485.


Therefore P(non-defective tubes) = 485/500.

                                                          = 0.97


Hope this helps!