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Let the age of the children will be x+x then their father's age will be 3(x+x)now you can calculate it by yourself i have just given a hint
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Heya!!
----I'm answering after long tym-------
Let the present age of two children's be x and y.
Then father's age = 3(x+y) - - eq1.
A/Q after five years ;
Sum of children's age = x+5+y+5
= x+y+10
Hence father's age = 2(x+y+10) + 5 - - eq2.
Since 3(x+y)+ 5 = 2(x+y+10)
=) 3x+3y + 5 = 2x+2y+20
=) 3x-2x + 3y-2y = 20-5
=) x+y = 15
Put value of (x+y) in eq1.
=) Father's age = 3(x+y)
= 3(15) = 45 years
-------------------------------------
Hope it helps u :)
----I'm answering after long tym-------
Let the present age of two children's be x and y.
Then father's age = 3(x+y) - - eq1.
A/Q after five years ;
Sum of children's age = x+5+y+5
= x+y+10
Hence father's age = 2(x+y+10) + 5 - - eq2.
Since 3(x+y)+ 5 = 2(x+y+10)
=) 3x+3y + 5 = 2x+2y+20
=) 3x-2x + 3y-2y = 20-5
=) x+y = 15
Put value of (x+y) in eq1.
=) Father's age = 3(x+y)
= 3(15) = 45 years
-------------------------------------
Hope it helps u :)
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