Question

pls ans , useless ans will be reported​

Answer 1

Answer:

A can do a piece of work in 6 days, that is he does 1/6th of the work in a day.

B can do it in 8 days, that is he does 1/8th of the work in a day.

Together they do 1/6 + 1/8 or 4/24+3/24 or 7/24th of the work in a day. So they complete the work in 24/7 days or

3 and 4/7th of a day.

Answer 2

Answer:

first we will find the lcm of given work A done the work in 6 days and B done the work in 8 days so the lcm of 6 and 8 is 24 so total which has to be done is 24 units A does the work in 1 day is =24/6 that is 4 units and B does the work in 1 day =24/8=3 units so if A and B will work together for 2 day the work done by them will be=4+3×2 that is 14 units the work left is 24-14=10 units. now B left the work so A will do the left work in 10/4 that is in 5/2 days A will finish the work