Math, asked by julisingh1w3, 4 months ago

pls ans with explaination or I will report your account ​

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Answers

Answered by ashishc1403
0

Answer:

Required number is 997920

Step-by-step explanation:

Given numbers are 27 , 45 , 60 , 72 and 96

We have to find greatest 6-digit number which is divisible by given numbers.

We first find lowest Common Multiple of given numbers then we find multiple of LCM which greatest 6 digit number.

27 = 3 × 3 × 3

45 = 5 × 3 × 3

60 = 2 × 3 × 2 × 5

72 = 2 × 2 × 2 × 3 × 3

96 = 2 × 2 × 2 × 2 × 2 × 3

LCM = 3 × 3 × 2 × 2 × 2 × 2 × 2 × 3 × 5 = 4320

Now we find the multiples of 4320 which is largest 6 digit number

for divide 999999 ÷ 4320 we get 231.48125

So, 231st multiple of 4320 is largest 6 digit number .i.e., 4320 × 231 = 997920

Therefore, required number is 997920

least number

Let's break all those down into prime factors:

27 = 3*3*3

45 = 3*3*5

60 = 2*2*3*5

72 = 2*2*2*3*3

96 = 2*2*2*2*2*3

Let's check to see which of those has the most 2 factors:

27 has 0 2's

45 has 0 2's

60 has 2 2's

72 has 3 2's

96 has 5 2's

The most in that list is 5 2's. So the LCM has 5 2's

27 = 3*3*3

45 = 3*3*5

60 = 2*2*3*5

72 = 2*2*2*3*3

96 = 2*2*2*2*2*3

Let's check to see which of those has the most 3 factors:

27 has 3 3's

45 has 2 3's

60 has 1 3

72 has 2 3's

96 has 1 3's

The most in that list is 3 3's. So the LCM has 5 2's and 3 3's

27 = 3*3*3

45 = 3*3*5

60 = 2*2*3*5

72 = 2*2*2*3*3

96 = 2*2*2*2*2*3

Let's check to see which of those has the most 5 factors:

27 has 0 5's

45 has 1 5

60 has 1 5

72 has 0 5's

96 has 0 5's

The most on that list is 1 5. So the LCM has 5 2's, 3 3's, and 1 5.

So LCM = 2*2*2*2*2*3*3*3*5 = 4320

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