Question

pls anssss very important​

Answer 1

4 a)

$(2a + \frac{b}{6} + 4c)²$

Find common denominator...

$( \frac{6 \times 2a}{6} + \frac{b}{6} + \frac{6 \times 4c}{6} ) {}^{2}$

Combine fractions with common denominator...

$(\frac{6 \times 2a + b + 6 \times 4c}{6} ) {}^{2}$

Multiply the numbers...

$( \frac{12a + b + 6 \times 4c}{6}) {}^{2}$

Multiply the numbers...

$(\frac{12a + b + 24c}{6} )$

$\huge \: answer = \: \: (\frac{12a + b + 24c}{6} )$

4 b)

a + b + c = 14

ab + bc + ac = 61

(a + b + c)² = (14)²

a² + b² + c² + 2(ab + bc + ac) = 196

a² + b² + c² + 2(61) = 196

a² + b² + c² + 122 = 196

a² + b² + c²= 196 - 122

a² + b² + c ² = 74

Answer = 74

$\huge{ son \: prodigal}$

Answer 2

a)

(2a + \frac{b}{6} + 4c)²(2a+

6

b

+4c)²

Find common denominator...

( \frac{6 \times 2a}{6} + \frac{b}{6} + \frac{6 \times 4c}{6} ) {}^{2}(

6

6×2a

+

6

b

+

6

6×4c

)

2

Combine fractions with common denominator...

(\frac{6 \times 2a + b + 6 \times 4c}{6} ) {}^{2}(

6

6×2a+b+6×4c

)

2

Multiply the numbers...

( \frac{12a + b + 6 \times 4c}{6}) {}^{2}(

6

12a+b+6×4c

)

2

Multiply the numbers...

(\frac{12a + b + 24c}{6} )(

6

12a+b+24c

)

\huge \: answer = \: \: (\frac{12a + b + 24c}{6} )answer=(

6

12a+b+24c

)

4 b)

a + b + c = 14

ab + bc + ac = 61

(a + b + c)² = (14)²

a² + b² + c² + 2(ab + bc + ac) = 196

a² + b² + c² + 2(61) = 196

a² + b² + c² + 122 = 196

a² + b² + c²= 196 - 122

a² + b² + c ² = 74

Answer = 74