Question

pls answer.............. ​

Answer 1

Solution :

The given equation is

x⁴ + x³ - 4x² + x + 1 = 0

Dividing both sides by x² (x ≠ 0), we get

x² + x - 4 + 1/x + 1/x² = 0

⇒ (x² + 1/x² + (x + 1/x) - 4 = 0

⇒ {(x + 1/x)² - (2 * x * 1/x)} + (x + 1/x) - 4 = 0

⇒ (y² - 2) + y - 4 = 0 [ ATQ ]

⇒ y² - 2 + y - 4 = 0

⇒ y² + y - 6 = 0 ,

which is the required reduced equation.

∴ option (c) is correct.