Question

pls answer 12 question ​

Answer 1

Answer:

According to question

2a*a +2b*b = a*a +b*b +2ab

therefore

a*a +b*b =2ab

a*a+ b*b +2ab=0

i.e.

(a+b)^2 =0

i.e.

a+b=0

proved

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Answer 2

GIVEN

$2( {a}^{2} + {b}^{2} ) = {(a + b)}^{2}$

SIMPLIFICATION

$2( {a}^{2} + {b}^{2} ) = {(a + b)}^{2} \\ \\ \\ \implies 2 {a}^{2} + 2 {b}^{2} = {a}^{2} + {b}^{2} + 2ab \\ \\ \\ \implies 2 {a}^{2} + {2b }^{2} - {a}^{2} - {b}^{2} = 2ab \\ \\ \\ \implies {a }^{2} + {b}^{2} - 2ab = 0 \\ \\ \\ \implies {(a - b)}^{2} = 0 \\ \\ \\ \implies a - b = 0 \\ \\ \\ \implies \: \boxed{a = b} \: \: (proved)$

Therefore option (B) is correct .

IDENTITIES USED

(a+b)^2 = a^2 + b^2 + 2ab

(a-b)^2 = a^2 + b^2 - 2ab