Question

pls answer..............​

Answer 1

$p(x) = x {}^{2} - 2 \sqrt[]{2}x + 1 \\ therefore \\ p(2 \sqrt{2}) =(2 \sqrt{2}) ^{2} - 2 \sqrt{2} \times 2 \sqrt{2} + 1 \\ 8 - 8 + 1 = 1$Hope you like my answer

Answer 2

Answer:1

Explanation:

P(X)=X²-2√2X+1

THEN

P(2√2)=?

P(2√2)=P(X)

∴P(2√2)=(2√2)²- 2√2(2√2)+1

             =8-8+1

             =1

∴P(2√2)= 1

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