Math, asked by Anonymous, 1 year ago

Pls answer 27th question Pls answer friends it's very urgent the best answer will be selected as brainliest

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Answered by praneethks
1
a=8+3√7. b=1/8+3√7 rationalise b by multiplying 8-3√7 to both numerator and denominator.
b=(8-3√7)/(8+3√7)(8-3√7)=8-3√7/64-63=8-3√7.
 {a}^{2} = {(8 + 3 \sqrt{7} ) }^{2} = {8}^{2} + {(3 \sqrt{7 })^{2} } +
2(8)(3 \sqrt{7} )
=>
 {a}^{2} = 64 + 63 - 48 \sqrt{7}
similarly we get
 = > {b}^{2} = 64 + 63 - 48 \sqrt{7}
 = > {b}^{2} = 127 - 48 \sqrt{7}
=> so a^2+b^2=127+48√7+127-
48√7 => a^2+b^2 =254 is the answer. hope it helps you...
Answered by Anonymous
0

Given, a and b
Let, a= x and b = 1/x
Now, (a+b)^2= x^2+ 1/x^2 + 2(x)(1/x)
= x^2+1/x^2+2...
That implies a^2 + b^2 = -2...



Hope it helps you...


Anonymous: The most akward situation when u know ur answer is wrong and still say hope it helps you.
Anonymous: I'm so sorry...
Anonymous: I truly apologize.
Anonymous: Hehehe....ok
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