Pls answer 27th question Pls answer friends it's very urgent the best answer will be selected as brainliest
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Answered by
1
a=8+3√7. b=1/8+3√7 rationalise b by multiplying 8-3√7 to both numerator and denominator.
b=(8-3√7)/(8+3√7)(8-3√7)=8-3√7/64-63=8-3√7.


=>

similarly we get


=> so a^2+b^2=127+48√7+127-
48√7 => a^2+b^2 =254 is the answer. hope it helps you...
b=(8-3√7)/(8+3√7)(8-3√7)=8-3√7/64-63=8-3√7.
=>
similarly we get
=> so a^2+b^2=127+48√7+127-
48√7 => a^2+b^2 =254 is the answer. hope it helps you...
Answered by
0
Given, a and b
Let, a= x and b = 1/x
Now, (a+b)^2= x^2+ 1/x^2 + 2(x)(1/x)
= x^2+1/x^2+2...
That implies a^2 + b^2 = -2...
Hope it helps you...
Anonymous:
The most akward situation when u know ur answer is wrong and still say hope it helps you.
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