pls answer 3rd question. this is urgent
I will mark as brainlist
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Hey friend,
Here is your answer,
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4x + 5z = 19 xz = 5
(4x+5z)³ = 19³
(4x)³ + (5z)³ + 3xz(4x+5z) = 19³ {Formula used :- a+b}³ = a³+b³+3ab(a+b)
64x³ + 125z³ + 3*5*19 = 6859
64x³ + 125z³ + 285 = 6859
64x³ + 125z³ = 6859 - 285
64x³ + 125z³ = 6574
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
Here is your answer,
______________________________________________________________
4x + 5z = 19 xz = 5
(4x+5z)³ = 19³
(4x)³ + (5z)³ + 3xz(4x+5z) = 19³ {Formula used :- a+b}³ = a³+b³+3ab(a+b)
64x³ + 125z³ + 3*5*19 = 6859
64x³ + 125z³ + 285 = 6859
64x³ + 125z³ = 6859 - 285
64x³ + 125z³ = 6574
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
AlwaysSmile:
is it ok now
Answered by
0
it is written as (4x)³+(5z)³
since acube +bcube = (a+b)((a+b)²-ab)
now put values
since acube +bcube = (a+b)((a+b)²-ab)
now put values
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