Question

Pls answer 4, 5 question

With examples and how u solve it pls

Answer 1

Answer:

4.)Let Swati earns Rs. 100.

Satish earns = 100 + 20% of 100 = 120.

Sahil earns = 120 + 10% of 120 = 132.

Earning difference of Sahil and Swati = 17500

132 - 100 = 17500

32 = 17500

1 = 17500/32

100 = (17500 * 100)/32 = Rs. 54687.5.

So, Swati earnings = Rs. 54687.5.

Sahil earnings = Rs. 72187.5.

Satish earning = 54687.5 + 20% of 54687.5 = Rs. 65625

5)let’s figure out the number of possible outcomes. Each has 6 possible outcomes (1, 2, 3, 4, 5, 6), so the combination of these two becomes 6 * 6 = 36.

In case you want to see why this is:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

where the first number in the parenthesis is the outcome of the first die and the second number is the outcome of the second die.

Now, of these 36 possible combinations, how many show the same number? Six of them:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

So then the probability of two rolled dice having the same number becomes 6/36, which reduces to 1/6.

P (not getting the same number on the two dice) =(1−1/6)=5/6.