Pls answer 6th question
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Hi,
According to the problem given ,
<BAO = <DCO ----( 1 )
OC = OD ---------( 2 )
1 ) In ∆DCO ,
< OCD = <DCO [ since OC = OD ] --( 3 )
<BAO = <DCO [ from ( 1 ) ]
<BAO = <DCO [ from ( 3 ) ] ---( 4 )
2 ) AB , CD are two line segments , AD is
a transversal.
<BAO = <DCO [ alternate angles are equal ]
Therefore ,
AB // CD
I hope this helps you.
: )
According to the problem given ,
<BAO = <DCO ----( 1 )
OC = OD ---------( 2 )
1 ) In ∆DCO ,
< OCD = <DCO [ since OC = OD ] --( 3 )
<BAO = <DCO [ from ( 1 ) ]
<BAO = <DCO [ from ( 3 ) ] ---( 4 )
2 ) AB , CD are two line segments , AD is
a transversal.
<BAO = <DCO [ alternate angles are equal ]
Therefore ,
AB // CD
I hope this helps you.
: )
Answered by
0
Answer:
ab/CD is answer pls mark as BRAINLIEST
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