Question

Pls answer 6th with full explanation

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given: O is any point on PR in parallelogram PQRS

To prove: ar(△PSO) = ar(△PQO)

Construction: Join SQ.

Proof:

Let diagonals PR and SQ intersect each other at N

∵ diagonals of a parallelogram bisect each other

∴ N is the mid - point of SQ

∵ a median of a triangle divides it into two triangles of equal area

∴ In △PQS , PN is its median

⇒  ar(△PNS) = ar(△PQN) (i)

∴ In △SQO, ON is its median

⇒  ar(△SNO) = (△QNO) (ii)  

Adding (i) and (ii) , we have  

ar(△PNS) + ar(△SNO) = ar(△PQN) = ar(△QNO )  

⇒ ar(△PSO) = ar(△PQO)

HOPE THIS HELPS

MARK AS BRAINLIEST ^_^