pls answer.........
Attachments:

Answers
Answered by
2
Force between the plates is given by
F=QE/2
Q=1mc =10^-6 C
E=10^5 V/M =10^5 N/C [Newton/Columbs)]
So F=10^5×10^-6/2
=10^-1/2
=1/20
=0.05 NAns
Similar questions
English,
8 months ago
English,
8 months ago
Business Studies,
8 months ago
Math,
1 year ago
Geography,
1 year ago
Math,
1 year ago
English,
1 year ago
Political Science,
1 year ago