Question

pls answer.........​

Answer 1

Force between the plates is given by

F=QE/2

Q=1mc =10^-6 C

E=10^5 V/M =10^5 N/C [Newton/Columbs)]

So F=10^5×10^-6/2

=10^-1/2

=1/20

=0.05 NAns