pls answer.............
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The answer is 69MF as I view this
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Answer:
Explanation:
Capacitors:-This is the configuration of a Wheatstone bridge.As a result potential difference across 24uF capacitor will be 0
So,no current can flow through it.Hence,we ignore that capacitor.
Now,6 and 12 are in series9 and 18 are in series.
C1=(6*12)/(6+12)=4uF
C2=(9*18)/(9+18)=6uF
Now,C1 and C2 are in parallel.
So,Cab=4+6=10uF
So, option D is correct.
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