Question

pls answer all 5 questions i will make you brainilist pls solve the student activity​

Answer 1

2)Total number of subsets =

12

C

4

=495

Now, find the subsets where the selected 4 numbers are non-consecutive.

For each such case, the non-consecutive numbers occupy any four of the gaps created by remaining 8 natural numbers.

Total number of gaps formed by 8 numbers is 9.

So the number of solutions is equivalent to filling any 4 out of 9 gaps obtained. This can be done in

9

C

4

=126 ways.

Hence, the number of subsets where atleast two numbers are consecutive is 495−126=369

Answer 2

Answer:

the answer of this question 369