Question

Pls Answer All Questions.Thanks​

Answer 1

Explanation:

1 quest answer

Step 1: Draw free body diagram and Resolving forces [Ref. Fig.]

Let f be the frictional force

As shown in the figure:

Resolving force mg along the inclined plane, we get mg sinθ

Resolving force mg perpendicular to the incline, we get mg cosθ

Step 2: Net force on block

Since the block is at rest, therefore net force acting on it along inclined direction is zero.

∑F

net

=0

⇒f−mgsinθ=0

⇒ 10=m×10×sin30

0

⇒ m=2kg

Hence, Option A is correct.

Note: There is no use of friction coefficient in this question.

Since the block is not slipping and the value of static friction is given. So, this value must be less than or equal to its maximum value (μN). Hence we need not compare it.

2nd question answer