Question

pls answer all the question .​

Answer 1

SOLUTION OF (3):-

x=1/2-root3

Multiply the numerator and denominator by the conjugate of the denominator.

x=1/2-root3 × 2+root3/2+root3

=2+root3/2^2-root3^2

=2+root3/4-3

=2+root3

x^2=(2+root3)^2

=4+4root3+3

=7+4root3

Now consider the given expression,

x^3 - 2x^2 - 7x + 5

=x^3-7x -2x^2+5

=x(x^2-7) - 2x^2 + 5

=(2+root3)(7+4root3-7)-2(7+4root3)+5

=(2+root3)(4root3) - 14 - 8root3 + 5

=8root3 + 12 -14 - 8root3 + 5

=3

Sorry baki 2 nahi aa raha.....