Question

pls answer all the questions I will follow and mark brainly ​

Answer 1

Step-by-step explanation:

a^2 / B + b^2/a

= a^3 + B^3 /ab ....(1)

we know that

(alpha + beta )^3 = a^3 + B^3 + 3aB ( a+b)

so,

(-a)^3 = a^3 +B^3 + 3 (b)(-a)

-a^3 +3ab = a^3 + B^3

a^3 + B^3 = -a^3 + 3ab /b Ans

2.Alpha + beta = -5/3

Alpha × beta =7/3

To find ,

1/a^3 + 1/b^3

( a ^3 +b^3 ) ( a×b^ 3)

(a+b)(a+b)^2 - 3ab ) / a×b^3

(-5/3)(-5/3)^2 - 3 × 7/3 /(7/3)^3

(-5/3)(25-63)/9) / (49 × 7)/27

(5×38) / (49×7)

190/ 343

3. Given quadratic polynomial is 2s^2 -(1+2√2 ) s + √2

2s ^2 - s - 2√2s +√2

s ( 2s - 1 ) - √2 ( 2s - 1)

( 2s - 1 ) ( s - √2)

s= 1/2 and s = √2

the relationship between the zeros and their coefficient

sum of zeroes = - coefficient of s / coefficient of s ^2

- ( - ( 1+2√2 )/2

1+2√2/2

Also sum of the zeroes = 1 /2 + √2

= 1 + 2 √2 /2

product of zeroes = constant term/ coefficient of s^2

√2/2

Also. the product of the zeroes = 1/2×√2

= √2/2

Hence verified

I hope it will help you