pls answer and explain it properly
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Step-by-step explanation:
given: 3^-n+3^1-n/3^-n-3^2-n
need to prove: -1/2
by solving,...
we know that a formula: a^-n= 1/a^n
so, 3^-n= 1/3^n
also, 3^1-n= 3^1.3^-n= 3/3^n
3^2-n= 3^2. 3^-n= 9/3^n
by substituting all the values in question as stated....we have...
= 1/3^n+3/3^n/1/3^n- 9/3^n
By taking LCM at numerator and denominator...
LCM= 3^n
4/3^n/-8/3^n
by cancelling 3^n in both denominators...
we have: 4/-8= -1/2
so answer: -1/2
Hence proved......
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