Question

Pls answer as fast as possible
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Answer 1

Step-by-step explanation:

${729}^{ - 2} \times {3}^{ - 5} \times {3}^{10} - {( \sqrt{25} - \sqrt{16} )}^{0}$

$= \frac{1}{ {3}^{6 \times2} } \times \frac{1}{ {3}^{5} } \times {3}^{10} - {(5 - 4)}^{0}$

$= \frac{ {3}^{10} }{ {3}^{12 + 5} } - 1$

$= \frac{ {3}^{10} }{ {3}^{17} } - 1$

$\frac{1}{ {3}^{7} } - 1$

Solve further by yourself to get the answer

Answer 2

Step-by-step explanation:

${729}^{ - 2} \times {3}^{ - 5} \times {3}^{10} - {( \sqrt{25} - \sqrt{16} )}^{0}$

${3}^{ - 6} \times {3}^{ - 5} \times {3}^{10} - 1$

${3}^{ - 6 - 5 + 10} - 1$

${3}^{ - 1} - 1$

$\frac{1}{3} - 1$

$\frac{1 - 3}{3}$

$\frac{ - 2}{3}$

HOPEFULLY THIS HELPS YOU...

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