Question

pls answer as fast as u can​

Answer 1

Answer:

please see the above attachment

hope you understand...

Answer 2

Answer:

given=>

ABCD is a parallelogram

to prove=>

BC= CD

proof=>

In ∆ ABC and ∆ ADC

ADC= ABC (opposite angle of parallelogram)

AC= AC ( common)

DCA = BAC ( alternate interior angle)

therefore, ∆ ABC congruence to ∆ ADC ( by angle side angle)

BC= CD [by CPCT( corresponding part of congruence triangle)]